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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2026, Shift 2, Physics Q32

Question 32 of 75 in this shift, Physics question 7 of 25, Section A.

In a screw gauge the zero of main scale reference line coincides with the fifth division of the circular scale when two studs are in contact. There are 100 divisions in circular scale and pitch of screw gauge is 0.1 mm. When diameter of a sphere is measured, the reading of main scale is 5 mm and 50th division of circular scale coincides with the reference line of main scale. The diameter of sphere is
  1. (1)5.0455.045 mmOfficial answer
  2. (2)5.0555.055 mm
  3. (3)5.4505.450 mm
  4. (4)5.5505.550 mm

Official answer

Option 1

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.