JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation
JEE Main 2 April 2026, Shift 2, Physics Q27
Question 27 of 75 in this shift, Physics question 2 of 25, Section A.
A 0.5 kg mass is in contact against the inner wall of a cylindrical drum of radius 4 m rotating about its vertical axis. The minimum rotational speed of the drum to enable the mass to remain stuck to the wall (without falling) is 5 rad/s. The coefficient of friction between the drum's inner wall surface and mass is
(Take m/s)
- (1)Official answer
- (2)
- (3)
- (4)
Official answer
Option 1
NTA final key.
- Chapter
- Laws of Motion
- Topic
- Friction
- Idea tested
- Rotor / Death Well Friction