If the area of the region bounded by $16x^2 - 9y^2 = 144$ and $8x - 3y = 24$ is $A$, then $3(A + 6\log_e(3))$ is equal to

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 2 April 2026, Shift 2, Maths Q24

Question 24 of 75 in this shift, Maths question 24 of 25, Section B.

If the area of the region bounded by

16x^2 - 9y^2 = 144

and

8x - 3y = 24

A

, then

3(A + 6\log_e(3))

is equal to

Official answer

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area Between Curves

Same idea in other shifts

Asked 12× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.