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JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 2, Maths Q10

Question 10 of 75 in this shift, Maths question 10 of 25, Section A.

Let a circle pass through the origin and its centre be the point of intersection of two mutually perpendicular lines

x + (k - 1)y + 3 = 0

and

2x + k^2y - 4 = 0

. If the line

x - y + 2 = 0

intersects the circle at the points

A

and

B

, then

(AB)^2

is equal to:

(1) $10$
(2) $27$
(3) $18$ Official answer
(4) $34$

Official answer

Option 3

NTA final key.

Chapter: Conic Sections
Topic: Straight Line Distance
Idea tested: Chord Length via Perpendicular Distance

Same idea in other shifts

Asked 2× in all

6 Apr 2026, Shift 1 · Q22Let the centre of the circle $x^2+y^2+2gx+2fy+25=0$ be in the first quadrant and lie on the line $2x-y=4$ . Let the area of an equilateral…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.