JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2026, Shift 1, Physics Q31

Question 31 of 75 in this shift, Physics question 6 of 25, Section A.

A particle is rotating in a circular path and at any instant its motion can be described as

\theta=\frac{5t^4}{40}-\frac{t^3}{3}

. The angular acceleration of the particle after

10

seconds is __________

\mathrm{rad/s^2}

(1) $150$
(2) $120$
(3) $130$ Official answer
(4) $170$

Official answer

Option 3

NTA final key.

Chapter: System of Particles and Rotational Motion
Topic: Circular Motion
Idea tested: Angular and Linear Kinematics

Same idea in other shifts

Asked 3× in all

5 Apr 2026, Shift 2 · Q30A wheel initially at rest is subjected to a uniform angular acceleration about its axis. In the first 2 s it rotates through an angle…EasySingle correct
8 Apr 2024, Shift 1 · Q32A clock has 75 cm, 60 cm long second hand and minute hand respectively. In 30 minutes duration the tip of second hand will travel $x$ …EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.