JEE Main 2 April 2026, Shift 1, Maths Q22

Question 22 of 75 in this shift, Maths question 22 of 25, Section B.

\sum_{k=1}^{n}a_k=6n^3

, then

\sum_{k=1}^{6}\left(\frac{a_{k+1}-a_k}{36}\right)^2

is equal to __________.

Official answer

NTA final key.

Chapter: Sequences and Series
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.