JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 1, Maths Q13

Question 13 of 75 in this shift, Maths question 13 of 25, Section A.

If the point of intersection of the lines

\frac{x+1}{3}=\frac{y+a}{5}=\frac{z+b+1}{7}

and

\frac{x-2}{1}=\frac{y-b}{4}=\frac{z-2a}{7}

lies on

xy

-plane, then the value of

a+b

is :

(1) $2$
(2) $5$
(3) $7$ Official answer
(4) $9$

Official answer

Option 3

NTA final key.

Chapter: Three Dimensional Geometry
Topic: Lines in 3D
Idea tested: Point of Intersection Calculation

Same idea in other shifts

Asked 3× in all

4 Apr 2025, Shift 2 · Q15Let A be the point of intersection of the lines $L_1:\frac{x-7}{1}=\frac{y-5}{0}=\frac{z-3}{-1}$ and…MediumSingle correct
29 Jan 2024, Shift 1 · Q16Let PQR be a triangle with $R(-1,4,2)$ . Suppose $M(2,1,2)$ is the mid point of PQ. The distance of the centroid of $\Delta PQR$ from the…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.