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JEE Main 2025 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 8 April 2025, Shift 2, Chemistry Q72

Question 72 of 75 in this shift, Chemistry question 22 of 25, Section B.

The energy of an electron in first Bohr orbit of H-atom is −13.6 eV. The magnitude of energy value of electron in the first excited state of

\mathrm{Be^{3+}}

is __________ eV (nearest integer value)

Official answer

54

NTA final key.

Chapter: Structure of Atom
Topic: Bohr's Atomic Theory
Idea tested: Total, Kinetic, and Potential Energy

Same idea in other shifts

Asked 2× in all

6 Apr 2024, Shift 2 · Q81For hydrogen atom, energy of an electron in first excited state is $-3.4$ eV, K.E. of the same electron of hydrogen atom is $x$ eV. Value…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.