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Friday, 9 October

JEE Main 2025 · ChemistryMultiple choiceMatch the listEasyRecall

JEE Main 8 April 2025, Shift 2, Chemistry Q64

Question 64 of 75 in this shift, Chemistry question 14 of 25, Section A.

Match the LIST-I with LIST-II LIST-I | LIST-II A. Carbocation | I. Species that can supply a pair of electrons. B. C-Free radical | II. Species that can receive a pair of electrons. C. Nucleophile | III. sp2\mathrm{sp^2} hybridized carbon with empty p-orbital. D. Electrophile | IV. sp2/sp3\mathrm{sp^2/sp^3} hybridized carbon with one unpaired electron. Choose the correct answer from the options given below:
  1. (1)A-III, B-IV, C-II, D-I
  2. (2)A-II, B-III, C-I, D-IV
  3. (3)A-IV, B-II, C-III, D-I
  4. (4)A-III, B-IV, C-I, D-IIOfficial answer

Official answer

Option 4

NTA final key.

Chapter
Organic Chemistry: Some Basic Principles and Techniques
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.