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Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 8 April 2025, Shift 2, Physics Q34

Question 34 of 75 in this shift, Physics question 9 of 25, Section A.

Two strings with circular cross section and made of same material, are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section R is v1v_1, and that in the other string having radius of cross section R/2 is v2v_2. Then v2v1=\frac{v_2}{v_1} =
  1. (1)4
  2. (2)2Official answer
  3. (3)8
  4. (4)2\sqrt{2}

Official answer

Option 2

NTA final key.

Chapter
Waves
Topic
Waves on Strings
Idea tested
Wave Speed on String

Same idea in other shifts

Asked 2× in all
  1. 28 Jul 2022, Shift 1 · Q39In the wave equation y=0.5sin⁡2πλ(400 t−x) my=0.5\sin\frac{2\pi}{\lambda}(400\,t-x)\ \mathrm{m} the velocity of the wave will be :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.