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Friday, 9 October

JEE Main 2025 · PhysicsNumerical answerNumerical valueMediumApplication

JEE Main 7 April 2025, Shift 2, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

A parallel plate capacitor has charge 5×10−65\times10^{-6} C. A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is 4×10−64\times10^{-6} C then the dielectric constant of the slab is __________.

Official answer

5

NTA final key.