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Friday, 9 October

JEE Main 2025 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 7 April 2025, Shift 2, Maths Q23

Question 23 of 75 in this shift, Maths question 23 of 25, Section B.

For t>−1t>-1, let αt\alpha_t and βt\beta_t be the roots of the equation ((t+2)1/7−1)x2+((t+2)1/6−1)x+((t+2)1/21−1)=0\left((t+2)^{1/7}-1\right)x^2+\left((t+2)^{1/6}-1\right)x+\left((t+2)^{1/21}-1\right)=0. If lim⁡t→−1+αt=a\lim_{t\to-1^+}\alpha_t=a and lim⁡t→−1+βt=b\lim_{t\to-1^+}\beta_t=b, then 72(a+b)272(a+b)^2 is equal to ________.

Official answer

98

NTA final key.