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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 2, Maths Q19

Question 19 of 75 in this shift, Maths question 19 of 25, Section A.

Let y=y(x)y=y(x) be the solution of the differential equation (x2+1)y′−2xy=(x4+2x2+1)cos⁡x(x^2+1)y'-2xy=(x^4+2x^2+1)\cos x, y(0)=1y(0)=1. Then ∫−33y(x) dx\int_{-3}^{3}y(x)\,dx is :
  1. (1)18
  2. (2)24Official answer
  3. (3)30
  4. (4)36

Official answer

Option 2

NTA final key.

  1. 2 Apr 2026, Shift 1 · Q20Let y=y(x)y=y(x) be the solution curve of the differential equation (1+sin⁡x)dydx+(y+1)cos⁡x=0(1+\sin x)\frac{dy}{dx}+(y+1)\cos x=0, y(0)=0y(0)=0. If the curve y=y(x)y=y(x)…MediumSingle correct
  2. 4 Apr 2026, Shift 2 · Q19Let y=y(x)y=y(x) be the solution of the differential equation:…HardSingle correct
  3. 5 Apr 2026, Shift 2 · Q25Let y=y(x)y=y(x) be the solution of the differential equation (tan⁡x)1/2 dy=(sec⁡3x−(tan⁡x)3/2 y)dx(\tan x)^{1/2}\,dy=\left(\sec^3 x-(\tan x)^{3/2}\,y\right)dx,…HardNumerical value
  4. 6 Apr 2026, Shift 1 · Q25Let y=y(x)y=y(x) be the solution of the differential equation…HardNumerical value
  5. 6 Apr 2026, Shift 2 · Q18Let f:R→Rf:\mathbf{R}\to\mathbf{R} be such that f(xy)=f(x)f(y)f(xy)=f(x)f(y), for all x,y∈Rx,y\in\mathbf{R} and f(0)≠0f(0)\neq0. Let g:[1,∞)→Rg:[1,\infty)\to\mathbf{R}…HardSingle correct
  6. 8 Apr 2026, Shift 2 · Q17Let y=y(x)y = y(x) be the solution of the differential equation x1−x2 dy+(y1−x2−xcos⁡−1x)dx=0x\sqrt{1-x^2}\,dy + \left(y\sqrt{1-x^2} - x\cos^{-1}x\right)dx = 0,…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.