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JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 1, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

Let

x_1, x_2, x_3, x_4

be in a geometric progression. If

2, 7, 9, 5

are subtracted respectively from

x_1, x_2, x_3, x_4

, then the resulting numbers are in an arithmetic progression. Then the value of

\frac{1}{24}(x_1 x_2 x_3 x_4)

is:

(1) $216$ Official answer
(2) $72$
(3) $36$
(4) $18$

Official answer

Option 1

NTA final key.

Chapter: Sequences and Series
Topic: AP and GP
Idea tested: Conditions for Three Terms in AP or GP

Same idea in other shifts

Asked 2× in all

2 Apr 2017 (offline) · Q68For any three positive real numbers a, b and c, $9(25a^2+b^2)+25(c^2-3ac)=15b(3a+c)$ . Then :HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.