Learn

Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceDiagram basedMediumCalculation

JEE Main 7 April 2025, Shift 1, Physics Q45

Question 45 of 75 in this shift, Physics question 20 of 25, Section A.

In the following circuit, the reading of the ammeter will be (Take Zener breakdown voltage = 4 V)

The figure, in words

12 V battery in series with a 100 ohm resistor; a Zener diode and a voltmeter V connected in parallel across the junction; then a 400 ohm resistor in series with an ammeter A completing the loop.
  1. (1)2424 mA
  2. (2)8080 mA
  3. (3)1010 mAOfficial answer
  4. (4)6060 mA

Official answer

Option 3

NTA final key.

Chapter
Semiconductor Electronics: Materials, Devices and Simple Circuits
Topic
Semiconductor Diodes
Idea tested
Zener Diode Regulation

Same idea in other shifts

Asked 4× in all
  1. 2 Apr 2025, Shift 1 · Q45A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V. For a 400 Ω400\ \Omega resistor connected…MediumSingle correct
  2. 29 Jan 2024, Shift 1 · Q48In the given circuit, the breakdown voltage of the Zener diode is 3.0 V. What is the value of IzI_z?MediumDiagram basedHas a figure
  3. 9 Jan 2020, Shift 2 · Q25The circuit shown below is working as a 8 V dc regulated voltage source. When 12 V is used as input, the power dissipated (in mW) in each…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.