JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 7 April 2025, Shift 1, Physics Q43

Question 43 of 75 in this shift, Physics question 18 of 25, Section A.

For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series is

(1) $3 : 4$
(2) $5 : 27$ Official answer
(3) $27 : 5$
(4) $5 : 36$

Official answer

Option 2

NTA final key.

Chapter: Atoms
Topic: Bohr's Atomic Model
Idea tested: Shortest and Longest Wavelengths

Same idea in other shifts

Asked 3× in all

6 Apr 2024, Shift 2 · Q48The longest wavelength associated with Paschen series is : (Given $R_H=1.097\times10^7$ SI unit)EasySingle correct
3 Aug 2021, Shift 2 · Q23The ratio of shortest wavelength to the largest wavelength in Brackett series of atomic spectra for hydrogen atom is $x : 25$ , where the…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.