Learn

Saturday, 10 October

JEE Main 2025 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 4 April 2025, Shift 2, Physics Q46

Question 46 of 75 in this shift, Physics question 21 of 25, Section B.

In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm. If the 20 maxima of the double slit pattern are contained within the central maximum of the single slit diffraction pattern, then the width of each slit is x×10−3x\times10^{-3} cm, where x-value is ______.

Official answer

15

NTA final key.