Learn

Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 4 April 2025, Shift 2, Physics Q40

Question 40 of 75 in this shift, Physics question 15 of 25, Section A.

Two polarisers P1P_1 and P2P_2 are placed in such a way that the intensity of the transmitted light will be zero. A third polariser P3P_3 is inserted in between P1P_1 and P2P_2, at particular angle between P2P_2 and P3P_3. The transmitted intensity of the light passing the through all three polarisers is maximum. The angle between the polarisers P2P_2 and P3P_3 is :
  1. (1)π/8\pi/8
  2. (2)π/6\pi/6
  3. (3)π3\frac{\pi}{3}
  4. (4)π4\frac{\pi}{4}Official answer

Official answer

Option 4

NTA final key.