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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 4 April 2025, Shift 2, Maths Q18

Question 18 of 75 in this shift, Maths question 18 of 25, Section A.

Let f(x)+2f(1x)=x2+5f(x)+2f\left(\frac{1}{x}\right)=x^2+5 and 2g(x)−3g(12)=x2g(x)-3g\left(\frac{1}{2}\right)=x, x>0x>0. If α=∫12f(x) dx\alpha=\int_1^2 f(x)\,dx, and β=∫12g(x) dx\beta=\int_1^2 g(x)\,dx, then the value of 9α+β9\alpha+\beta is :
  1. (1)0
  2. (2)1
  3. (3)10
  4. (4)11Official answer

Official answer

Option 4

NTA final key.

Chapter
Integrals
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.