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Saturday, 10 October

JEE Main 2025 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 3 April 2025, Shift 2, Chemistry Q71

Question 71 of 75 in this shift, Chemistry question 21 of 25, Section B.

A perfect gas (0.1 mol) having C‾v=1.50R\overline{\mathrm{C}}_v = 1.50\mathrm{R} (independent of temperature) undergoes the above transformation from point 1 to point 4. If each step is reversible, the total work done (w) while going from point 1 to point 4 is (-) __________ J (nearest integer) [Given: R = 0.082 L atm K−1 mol−1\mathrm{K^{-1}\,mol^{-1}}]

The figure, in words

P-V diagram (P/atm vs V/cm^3): point 1 at (1000 cm^3, 1.00 atm); vertical line up to point 2 at (1000, 3.00 atm); horizontal line to point 3 at (2000, 3.00 atm); vertical line down to point 4 at (2000, 1.00 atm). Arrows show direction 1->2->3->4.

Official answer

304

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.