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Friday, 9 October

JEE Main 2025 · ChemistryMultiple choiceDiagram basedHardMulti-step

JEE Main 3 April 2025, Shift 2, Chemistry Q69

Question 69 of 75 in this shift, Chemistry question 19 of 25, Section A.

The sequence from the following that would result in giving predominantly 3, 4, 5-Tribromoaniline is :

The figure, in words

Each option is a starting benzene derivative drawn as a ring (aniline; nitrobenzene; 4-nitroaniline; benzene) with the reagent sequence written over the arrow.
  1. (1)Aniline, Br2\mathrm{Br_2}, water
  2. (2)Nitrobenzene, (i) Br2\mathrm{Br_2}, acetic acid (ii) Sn, HCl
  3. (3)4-Nitroaniline (ring with NH2\mathrm{NH_2} and para NO2\mathrm{NO_2}), (i) Br2\mathrm{Br_2} (excess), acetic acid (ii) NaNO2\mathrm{NaNO_2}, HCl, CuBr (iii) Sn, HClOfficial answer
  4. (4)Benzene, (i) Br2,AlBr3\mathrm{Br_2, AlBr_3} (ii) NH3\mathrm{NH_3}

Official answer

Option 3

NTA final key.

Chapter
Amines
Topic
Amines