Learn

Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 3 April 2025, Shift 1, Maths Q8

Question 8 of 75 in this shift, Maths question 8 of 25, Section A.

If ∑r=19(r+32r)⋅9Cr=α(32)9−β\sum_{r=1}^{9}\left(\frac{r+3}{2^r}\right)\cdot {}^9C_r = \alpha\left(\frac{3}{2}\right)^9 - \beta, α,β∈N\alpha, \beta \in \mathbb{N}, then (α+β)2(\alpha + \beta)^2 is equal to
  1. (1)27
  2. (2)18
  3. (3)9
  4. (4)81Official answer

Official answer

Option 4

NTA final key.