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JEE Main 3 April 2025, Shift 1, Chemistry Q71

Question 71 of 75 in this shift, Chemistry question 21 of 25, Section B.

Given :

\Delta H^{\ominus}_{sub}

[C (graphite)] = 710 kJ mol

^{-1}

\Delta_{C-H}H^{\ominus}

= 414 kJ mol

^{-1}

\Delta_{H-H}H^{\ominus}

= 436 kJ mol

^{-1}

\Delta_{C=C}H^{\ominus}

= 611 kJ mol

^{-1}

The

\Delta H_f^{\ominus}

for

\mathrm{CH_2 = CH_2}

is ______ kJ mol

^{-1}

(nearest integer value)

Official answer

NTA final key.

Same idea in other shifts