Learn

Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 3 April 2025, Shift 1, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

Let a1,a2,a3,…a_1, a_2, a_3, \ldots be a G.P. of increasing positive numbers. If a3a5=729a_3 a_5 = 729 and a2+a4=1114a_2 + a_4 = \frac{111}{4}, then 24 (a1+a2+a3)24\,(a_1 + a_2 + a_3) is equal to
  1. (1)128
  2. (2)129Official answer
  3. (3)130
  4. (4)131

Official answer

Option 2

NTA final key.

Idea tested
GP General Term