Learn

Friday, 9 October

JEE Main 2025 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 3 April 2025, Shift 1, Physics Q47

Question 47 of 75 in this shift, Physics question 22 of 25, Section B.

A 4.0 cm long straight wire carrying a current of 8A is placed perpendicular to a uniform magnetic field of strength 0.15 T. The magnetic force on the wire is ______ mN.

Official answer

48

NTA final key.

Chapter
Moving Charges and Magnetism
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.