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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 3 April 2025, Shift 1, Maths Q11

Question 11 of 75 in this shift, Maths question 11 of 25, Section A.

The radius of the smallest circle which touches the parabolas y=x2+2y = x^2 + 2 and x=y2+2x = y^2 + 2 is
  1. (1)722\frac{7\sqrt{2}}{2}
  2. (2)7216\frac{7\sqrt{2}}{16}
  3. (3)724\frac{7\sqrt{2}}{4}
  4. (4)728\frac{7\sqrt{2}}{8}Official answer

Official answer

Option 4

NTA final key.