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Friday, 9 October

JEE Main 2025 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 2 April 2025, Shift 2, Chemistry Q72

Question 72 of 75 in this shift, Chemistry question 22 of 25, Section B.

0.2%0.2\% (w/v) solution of NaOH is measured to have resistivity 870.0 mΩ m870.0\ \mathrm{m\Omega\ m}. The molar conductivity of the solution will be __________ ×102 mS dm2 mol−1\times10^2\ \mathrm{mS\ dm^2\ mol^{-1}}. (Nearest integer)

Official answer

23

NTA final key.

Chapter
Electrochemistry
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.