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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 2, Maths Q5

Question 5 of 75 in this shift, Maths question 5 of 25, Section A.

The number of terms of an A.P. is even; the sum of all the odd terms is 24, the sum of all the even terms is 30 and the last term exceeds the first by 212\frac{21}{2}. Then the number of terms which are integers in the A.P. is :
  1. (1)44Official answer
  2. (2)66
  3. (3)88
  4. (4)1010

Official answer

Option 1

NTA final key.

Same topic in other shifts

All AP and GP questions
  1. 2 Apr 2026, Shift 1 · Q5Let AA be the set of first 101101 terms of an A.P., whose first term is 11 and the common difference is 55 and let BB be the set of…MediumSingle correct
  2. 2 Apr 2026, Shift 2 · Q4Let a1,a2,a3,…a_1, a_2, a_3, \ldots be an A.P. and g1,g2,g3,…g_1, g_2, g_3, \ldots be an increasing G.P. If a1=a2+g2=1a_1 = a_2 + g_2 = 1 and a3+g3=4a_3 + g_3 = 4,…MediumSingle correct
  3. 2 Apr 2026, Shift 2 · Q5The sum 131+13+231+3+13+23+331+3+5+…\frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \ldots up to 8 terms, is:MediumSingle correct
  4. 4 Apr 2026, Shift 1 · Q7The first term of an A.P. of 3030 non-negative terms is 103\frac{10}{3}. If the sum of this A.P. is the cube of its last term, then its…MediumSingle correct
  5. 4 Apr 2026, Shift 2 · Q7Let α=14+18+116+…∞\alpha=\frac14+\frac18+\frac1{16}+\ldots\infty and β=13+19+127+…∞\beta=\frac13+\frac19+\frac1{27}+\ldots\infty. Then the value of…EasySingle correct
  6. 5 Apr 2026, Shift 1 · Q2Let the sum of the first nn terms of an A.P. be 3n2+5n3n^2 + 5n. Then the sum of squares of the first 10 terms of the A.P. is:EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.