Learn

Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 2, Physics Q45

Question 45 of 75 in this shift, Physics question 20 of 25, Section A.

In a moving coil galvanometer, two moving coils M1M_1 and M2M_2 have the following particulars : R1=5 ΩR_1 = 5\ \Omega, N1=15N_1 = 15, A1=3.6×10−3 m2A_1 = 3.6\times10^{-3}\ \mathrm{m^2}, B1=0.25B_1 = 0.25 T R2=7 ΩR_2 = 7\ \Omega, N2=21N_2 = 21, A2=1.8×10−3 m2A_2 = 1.8\times10^{-3}\ \mathrm{m^2}, B2=0.50B_2 = 0.50 T Assuming that torsional constant of the springs are same for both coils, what will be the ratio of voltage sensitivity of M1M_1 and M2M_2 ?
  1. (1)1:11:1Official answer
  2. (2)1:21:2
  3. (3)1:31:3
  4. (4)1:41:4

Official answer

Option 1

NTA final key.

Chapter
Moving Charges and Magnetism
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.