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Friday, 9 October

JEE Main 2025 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 2 April 2025, Shift 2, Maths Q25

Question 25 of 75 in this shift, Maths question 25 of 25, Section B.

Let y=y(x)y = y(x) be the solution of the differential equation dydx+2ysec⁡2x=2sec⁡2x+3tan⁡x⋅sec⁡2x\frac{\mathrm{d}y}{\mathrm{d}x} + 2y\sec^2 x = 2\sec^2 x + 3\tan x\cdot\sec^2 x such that y(0)=54y(0) = \frac{5}{4}. Then 12(y(π4)−e−2)12\left(y\left(\frac{\pi}{4}\right) - e^{-2}\right) is equal to __________.

Official answer

21

NTA final key.