/

Learn

Friday, 9 October

/

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 2, Maths Q2

Question 2 of 75 in this shift, Maths question 2 of 25, Section A.

Let

A = \{1, 2, 3, \ldots, 100\}

and

R

be a relation on

A

such that

R = \{(a, b) : a = 2b + 1\}

. Let

(a_1, a_2), (a_2, a_3), (a_3, a_4), \ldots, (a_k, a_{k+1})

be a sequence of

k

elements of

R

such that the second entry of an ordered pair is equal to the first entry of the next ordered pair. Then the largest integer

k

, for which such a sequence exists, is equal to :

(1) $5$ Official answer
(2) $6$
(3) $7$
(4) $8$

Official answer

Option 1

NTA final key.

Chapter: Relations and Functions
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.