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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2025, Shift 2, Maths Q18

Question 18 of 75 in this shift, Maths question 18 of 25, Section A.

4∫01(13+x2+1+x2)dx−3log⁡e(3)4\int_0^1 \left(\frac{1}{\sqrt{3+x^2}+\sqrt{1+x^2}}\right)\mathrm{d}x - 3\log_e(\sqrt{3}) is equal to :
  1. (1)2+2−log⁡e(1+2)2+\sqrt{2}-\log_e(1+\sqrt{2})
  2. (2)2−2−log⁡e(1+2)2-\sqrt{2}-\log_e(1+\sqrt{2})Official answer
  3. (3)2+2+log⁡e(1+2)2+\sqrt{2}+\log_e(1+\sqrt{2})
  4. (4)2−2+log⁡e(1+2)2-\sqrt{2}+\log_e(1+\sqrt{2})

Official answer

Option 2

NTA final key.

Chapter
Integrals

Same topic in other shifts

All Integration by Parts questions
  1. 9 Apr 2024, Shift 2 · Q12The value of the integral ∫−12log⁡e(x+x2+1)dx\int_{-1}^{2}\log_e\left(x+\sqrt{x^2+1}\right)dx isMediumSingle correct
  2. 6 Apr 2023, Shift 1 · Q11Let I(x)=∫x2(xsec⁡2x+tan⁡x)(xtan⁡x+1)2 dxI(x)=\int\frac{x^2(x\sec^2x+\tan x)}{(x\tan x+1)^2}\,dx. If I(0)=0I(0)=0, then I(π4)I\left(\frac{\pi}{4}\right) is equal toHardSingle correct
  3. 11 Apr 2023, Shift 1 · Q15The value of the integral ∫−log⁡e2log⁡e2ex(log⁡e(ex+1+e2x))dx\int_{-\log_e 2}^{\log_e 2} e^x\left(\log_e\left(e^x + \sqrt{1+e^{2x}}\right)\right)dx is equal toHardSingle correct
  4. 11 Apr 2023, Shift 1 · Q26For m,n>0m, n > 0, let α(m,n)=∫02tm(1+3t)n dt\alpha(m, n) = \int_0^2 t^m(1+3t)^n\,dt. If 11 α(10,6)+18 α(11,5)=p (14)611\,\alpha(10, 6) + 18\,\alpha(11, 5) = p\,(14)^6, then pp is equal…HardNumerical value
  5. 2 Apr 2017 (offline) · Q74Let In=∫tan⁡nx dx, (n>1)I_n=\int\tan^n x\,dx,\ (n>1). If I4+I6=atan⁡5x+bx5+CI_4+I_6=a\tan^5x+bx^5+C, where C is a constant of integration, then the ordered pair (a, b) is…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.