Learn

Friday, 9 October

JEE Main 2025 · ChemistryMultiple choiceTwo statementsMediumConceptual

JEE Main 2 April 2025, Shift 1, Chemistry Q68

Question 68 of 75 in this shift, Chemistry question 18 of 25, Section A.

Given below are two statements : Statement (I) : Vanillin ([structure: benzene ring with -CHO, -OH para to CHO and -OCH3 ortho to OH]) will react with NaOH and also with Tollen's reagent. Statement (II) : Vanillin ([structure: benzene ring with -CHO, -OH para to CHO and -OCH3 ortho to OH]) will undergo self aldol condensation very easily. In the light of the above statements, choose the most appropriate answer from the options given below :

The figure, in words

Vanillin structure (4-hydroxy-3-methoxybenzaldehyde): benzene ring with CHO, HO at the para position to CHO and OCH3 adjacent to the OH; drawn in both statements.
  1. (1)Both Statement I and Statement II are correct
  2. (2)Both Statement I and Statement II are incorrect
  3. (3)Statement I is correct but Statement II is incorrectOfficial answer
  4. (4)Statement I is incorrect but Statement II is correct

Official answer

Option 3

NTA final key.

Same topic in other shifts

All Aldol and Cannizzaro questions
  1. 2 Apr 2026, Shift 2 · Q66An organic compound 'x' where molar ratio of C, O and H are equal, on treatment with 50% KOH under reflux followed by acidification…MediumSingle correct
  2. 6 Apr 2026, Shift 2 · Q64'xx' is the product which is obtained by the hydrolysis of prop-1-yne in the presence of mercuric sulphate under dilute acidic medium at…MediumSingle correct
  3. 3 Apr 2025, Shift 2 · Q68The major product (P) in the following reaction is : Ph−CO−CHO\mathrm{Ph{-}CO{-}CHO} →ΔKOH\xrightarrow[\Delta]{\mathrm{KOH}} P (Major Product)MediumDiagram basedHas a figure
  4. 8 Apr 2025, Shift 2 · Q68When [structure: CH3C(=O)CH2CH2CH2CH2CHO\mathrm{CH_3C(=O)CH_2CH_2CH_2CH_2CHO}, a skeletal zigzag chain with a methyl ketone at one end and an aldehyde (C=O…MediumSingle correctHas a figure
  5. 30 Jan 2024, Shift 2 · Q78m-chlorobenzaldehyde on treatment with 50% KOH solution yieldsEasyDiagram basedHas a figure
  6. 25 Jul 2021, Shift 1 · Q44[figure: 3,3-dimethylcyclopentanone (ketone C=O, gem-dimethyl on adjacent ring carbon) reacts with CH3CHO\mathrm{CH_3CHO}, NaOH to give 'P'…HardSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.