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JEE Main 2025 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 1, Chemistry Q57

Question 57 of 75 in this shift, Chemistry question 7 of 25, Section A.

Among

\mathrm{SO_2}

,

\mathrm{NF_3}

,

\mathrm{NH_3}

,

\mathrm{XeF_2}

,

\mathrm{ClF_3}

and

\mathrm{SF_4}

, the hybridization of the molecule with non-zero dipole moment and highest number of lone-pairs of electrons on the central atom is :

(1) $dsp^2$
(2) $sp^3d$ Official answer
(3) $sp^3d^2$
(4) $sp^3$

Official answer

Option 2

NTA final key.

Chapter: Chemical Bonding and Molecular Structure
Topic: VSEPR Theory
Idea tested: VSEPR Symmetry and Dipole Moments

Same idea in other shifts

Asked 2× in all

30 Jan 2024, Shift 2 · Q62Given below are two statements: Statement - I: Since Fluorine is more electronegative than nitrogen, the net dipole moment of…MediumTwo statements

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.