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Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 1, Physics Q26

Question 26 of 75 in this shift, Physics question 1 of 25, Section A.

The equation for real gas is given by (P+aV2)(V−b)=RT\left(P+\frac{a}{V^2}\right)(V-b)=RT, where P,V,T and R are the pressure, volume, temperature and gas constant, respectively. The dimension of ab−2ab^{-2} is equivalent to that of :
  1. (1)Compressibility
  2. (2)Energy densityOfficial answer
  3. (3)Planck's constant
  4. (4)Strain

Official answer

Option 2

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.