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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2025, Shift 1, Maths Q10

Question 10 of 75 in this shift, Maths question 10 of 25, Section A.

Let one focus of the hyperbola H:x2a2−y2b2=1\mathrm{H}: \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 be at (10,0)(\sqrt{10},0) and the corresponding directrix be x=910x=\frac{9}{\sqrt{10}}. If ee and ll respectively are the eccentricity and the length of the latus rectum of H, then 9(e2+l)9(e^2+l) is equal to :
  1. (1)12
  2. (2)16Official answer
  3. (3)15
  4. (4)14

Official answer

Option 2

NTA final key.

Chapter
Conic Sections
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.