JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 31 January 2024, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

Force between two point charges

q_1

and

q_2

placed in vacuum at 'r' cm apart is

F

. Force between them when placed in a medium having dielectric constant

K=5

at 'r/5' cm apart will be:

(1) $F/5$
(2) $5F$ Official answer
(3) $F/25$
(4) $25F$

Official answer

Option 2

NTA final key.

Chapter: Electric Charges and Fields
Topic: Coulomb's Law
Idea tested: Medium Dielectric Effect

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.