JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyApplication

JEE Main 31 January 2024, Shift 1, Chemistry Q88

Question 88 of 90 in this shift, Chemistry question 28 of 30, Section B.

\mathrm{CH_3CH_2Br + NaOH}

with

\mathrm{C_2H_5OH}

gives Product A, and with

\mathrm{H_2O}

gives Product B. The total number of hydrogen atoms in product A and product B is _________.

The figure, in words

Reaction scheme: CH3CH2Br + NaOH branches to Product A (solvent C2H5OH, top arrow) and Product B (solvent H2O, bottom arrow)

Official answer

NTA final key.

Chapter: Haloalkanes and Haloarenes
Topic: SN1 and SN2 Mechanisms
Idea tested: Temperature Effects on Substitution vs Elimination

Same topic in other shifts

All SN1 and SN2 Mechanisms questions

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.