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Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 31 January 2024, Shift 1, Chemistry Q65

Question 65 of 90 in this shift, Chemistry question 5 of 30, Section A.

Integrated rate law equation for a first order gas phase reaction is given by (where Pi\mathrm{P_i} is initial pressure and Pt\mathrm{P_t} is total pressure at time tt)
  1. (1)k=2.303t×log⁡(2Pi−Pt)Pi\mathrm{k}=\frac{2.303}{\mathrm{t}}\times\log\frac{\left(2\mathrm{P_i}-\mathrm{P_t}\right)}{\mathrm{P_i}}
  2. (2)k=2.303t×log⁡Pi(2Pi−Pt)\mathrm{k}=\frac{2.303}{\mathrm{t}}\times\log\frac{\mathrm{P_i}}{\left(2\mathrm{P_i}-\mathrm{P_t}\right)}Official answer
  3. (3)k=2.303t×log⁡2Pi(2Pi−Pt)\mathrm{k}=\frac{2.303}{\mathrm{t}}\times\log\frac{2\mathrm{P_i}}{\left(2\mathrm{P_i}-\mathrm{P_t}\right)}
  4. (4)k=2.303t×Pi(2Pi−Pt)\mathrm{k}=\frac{2.303}{\mathrm{t}}\times\frac{\mathrm{P_i}}{\left(2\mathrm{P_i}-\mathrm{P_t}\right)}

Official answer

Option 2

NTA final key.