JEE Main 2024 (31 Jan, Shift 1) Chemistry Q63: Equilibrium

Question

For the given reaction, choose the correct expression of $\mathrm{K_C}$ from the following :-
$\mathrm{Fe^{3+}_{(aq)}+SCN^{-}_{(aq)}\rightleftharpoons(FeSCN)^{2+}_{(aq)}}$

Accepted Answer

Option 3: $\mathrm{K_C}=\frac{\left[\mathrm{FeSCN^{2+}}\right]}{\left[\mathrm{Fe^{3+}}\right]\left[\mathrm{SCN^-}\right]}$

Answer

$\mathrm{K_C}=\frac{\left[\mathrm{FeSCN^{2+}}\right]^2}{\left[\mathrm{Fe^{3+}}\right]\left[\mathrm{SCN^-}\right]}$

Answer

$\mathrm{K_C}=\frac{\left[\mathrm{FeSCN^{2+}}\right]}{\left[\mathrm{Fe^{3+}}\right]^2\left[\mathrm{SCN^-}\right]^2}$

Answer

$\mathrm{K_C}=\frac{\left[\mathrm{FeSCN^{2+}}\right]}{\left[\mathrm{Fe^{3+}}\right]\left[\mathrm{SCN^-}\right]}$

Answer

$\mathrm{K_C}=\frac{\left[\mathrm{Fe^{3+}}\right]\left[\mathrm{SCN^-}\right]}{\left[\mathrm{FeSCN^{2+}}\right]}$

JEE Main 31 January 2024, Shift 1, Chemistry Q63

Same idea in other shifts