JEE Main 2024 (31 Jan, Shift 1) Physics Q40: Electric Field

Question

Two charges $q$ and $3q$ are separated by a distance 'r ' in air. At a distance $x$ from charge $q$, the resultant electric field is zero. The value of $x$ is :

Accepted Answer

Option 3: $\frac{r}{\left(1+\sqrt{3}\right)}$

Answer

$r\left(1+\sqrt{3}\right)$

Answer

$\frac{\left(1+\sqrt{3}\right)}{r}$

Answer

$\frac{r}{\left(1+\sqrt{3}\right)}$

Answer

$\frac{r}{3\left(1+\sqrt{3}\right)}$

JEE Main 31 January 2024, Shift 1, Physics Q40

Same idea in other shifts