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Friday, 9 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 30 January 2024, Shift 2, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

NO2\mathrm{NO_2} required for a reaction is produced by decomposition of N2O5\mathrm{N_2O_5} in CCl4\mathrm{CCl_4} as by equation 2N2O5(g)→4NO2(g)+O2(g)2\mathrm{N_2O_{5(g)}} \to 4\mathrm{NO_{2(g)}} + \mathrm{O_{2(g)}} The initial concetration. of N2O5\mathrm{N_2O_5} is 3 mol L−1^{-1} and it is 2.75 mol L−1^{-1} after 30 minutes. The rate of formation of NO2\mathrm{NO_2} is x ×\times 10−3^{-3} mol L−1^{-1} min−1^{-1}, value of x is ________. (nearest integer)

Official answer

17

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 11 Apr 2023, Shift 1 · Q87KClO3+6FeSO4+3H2SO4→KCl+3Fe2(SO4)3+3H2O\mathrm{KClO_3 + 6FeSO_4 + 3H_2SO_4 \rightarrow KCl + 3Fe_2(SO_4)_3 + 3H_2O} The above reaction was studied at 300 K by monitoring the…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.