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Friday, 9 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 30 January 2024, Shift 2, Physics Q44

Question 44 of 90 in this shift, Physics question 14 of 30, Section A.

If the total energy transferred to a surface in time t is 6.48×105 J6.48\times 10^5\,J, then the magnitude of the total momentum delivered to this surface for complete absorption will be:
  1. (1)2.16×10−3 kg m/s2.16\times 10^{-3}\ kg\,m/sOfficial answer
  2. (2)4.32×10−3 kg m/s4.32\times 10^{-3}\ kg\,m/s
  3. (3)1.58×10−3 kg m/s1.58\times 10^{-3}\ kg\,m/s
  4. (4)2.46×10−3 kg m/s2.46\times 10^{-3}\ kg\,m/s

Official answer

Option 1

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.