JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 30 January 2024, Shift 2, Physics Q41

Question 41 of 90 in this shift, Physics question 11 of 30, Section A.

When a potential difference

V

is applied across a wire of resistance

R

, it dissipates energy at a rate

W

. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the energy dissipation rate will become:

(1) $2W$
(2) $1/2W$
(3) $4W$ Official answer
(4) $1/4W$

Official answer

Option 3

NTA final key.

Chapter: Current Electricity
Topic: Ohm's Law and Resistance
Idea tested: Resistance of Cut and Recombined Uniform Wires

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.