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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctHardConceptual

JEE Main 30 January 2024, Shift 1, Maths Q9

Question 9 of 90 in this shift, Maths question 9 of 30, Section A.

Let g:R→Rg:\mathbf{R}\to\mathbf{R} be a non constant twice differentiable function such that g′(12)=g′(32)g'\left(\frac{1}{2}\right)=g'\left(\frac{3}{2}\right). If a real valued function ff is defined as f(x)=12[g(x)+g(2−x)]f(x)=\frac{1}{2}[g(x)+g(2-x)], then
  1. (1)f′′(x)=0f''(x)=0 for atleast two xx in (0,2)(0,2)Official answer
  2. (2)f′′(x)=0f''(x)=0 for exactly one xx in (0,1)(0,1)
  3. (3)f′′(x)=0f''(x)=0 for no xx in (0,1)(0,1)
  4. (4)f′(32)+f′(12)=1f'\left(\frac{3}{2}\right)+f'\left(\frac{1}{2}\right)=1

Official answer

Option 1

NTA final key.