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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumData or graph

JEE Main 30 January 2024, Shift 1, Chemistry Q83

Question 83 of 90 in this shift, Chemistry question 23 of 30, Section B.

[Graph: V (dm3^3) on the vertical axis (marks 10, 20, 30) versus P (kPa) on the horizontal axis (marks 10, 20, 30). Point A at P = 10 kPa, V = 10 dm3^3; point B at P = 10 kPa, V = 30 dm3^3; point C at P = 30 kPa, V = 10 dm3^3. Path A to B is vertical (upward arrow), B to C is a straight sloping line (arrow pointing down-right), C to A is horizontal (arrow pointing left).] An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A→\toB→\toC→\toA as shown in the diagram above. The total work done in the process is ________ J.

The figure, in words

P-V cycle: V (dm^3) vertical axis 10,20,30; P (kPa) horizontal axis 10,20,30. A=(P 10, V 10), B=(P 10, V 30), C=(P 30, V 10). A->B vertical up, B->C straight diagonal down to the right, C->A horizontal back to the left.

Official answer

200

NTA final key.

Chapter
Thermodynamics (Chemistry)
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.