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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 30 January 2024, Shift 1, Physics Q56

Question 56 of 90 in this shift, Physics question 26 of 30, Section B.

Two cells are connected in opposition as shown. Cell E1E_1 is of 8 V emf and 2 Ω2\ \Omega internal resistance; the cell E2E_2 is of 2 V emf and 4 Ω4\ \Omega internal resistance. The terminal potential difference of cell E2E_2 is ________ V.

The figure, in words

Closed loop with two cells E1 and E2 connected in series opposition between points A, B (junction) and C, with no external resistor.

Official answer

6

NTA final key.

Chapter
Current Electricity
Topic
Kirchhoff's Laws
Idea tested
Reversed Cells in Series

Same idea in other shifts

Asked 2× in all
  1. 24 Feb 2021, Shift 1 · Q12A cell E1E_1 of emf 6 V and internal resistance 2 Ω\Omega is connected with another cell E2E_2 of emf 4 V and internal resistance 8…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.