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JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyApplication

JEE Main 29 January 2024, Shift 1, Chemistry Q61

Question 61 of 90 in this shift, Chemistry question 1 of 30, Section A.

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is :

(1) $5,0,0,+\frac{1}{2}$ Official answer
(2) $5,1,0,+\frac{1}{2}$
(3) $5,1,1,+\frac{1}{2}$
(4) $5,0,1,+\frac{1}{2}$

Official answer

Option 1

NTA final key.

Chapter: Structure of Atom
Topic: Quantum Numbers
Idea tested: Quantum Numbers of the Differentiating Electron

Same idea in other shifts

Asked 2× in all

31 Jan 2024, Shift 2 · Q62The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) areEasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.