JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 29 January 2024, Shift 1, Physics Q35

Question 35 of 90 in this shift, Physics question 5 of 30, Section A.

The potential energy function (in J) of a particle in a region of space is given as

U=(2x^2+3y^3+2z)

. Here

x

y

and

z

are in meter. The magnitude of

x

- component of force (in N) acting on the particle at point

P(1,2,3)

m is :

(1) $2$
(2) $4$ Official answer
(3) $6$
(4) $8$

Official answer

Option 2

NTA final key.

Chapter: Work, Energy and Power
Topic: Work and Kinetic Energy
Idea tested: Potential Energy from Conservative Force

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All Work and Kinetic Energy questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.