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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 29 January 2024, Shift 1, Maths Q12

Question 12 of 90 in this shift, Maths question 12 of 30, Section A.

For x∈(−π2,π2)x\in\left(-\frac{\pi}{2},\frac{\pi}{2}\right), if y(x)=∫cosec x+sin⁡xcosec xsec⁡x+tan⁡xsin⁡2xdxy(x)=\int\frac{\mathrm{cosec}\,x+\sin x}{\mathrm{cosec}\,x\sec x+\tan x\sin^2x}dx, and lim⁡x→(π2)−y(x)=0\lim_{x\to\left(\frac{\pi}{2}\right)^-}y(x)=0 then y(π4)y\left(\frac{\pi}{4}\right) is equal to
  1. (1)tan⁡−1(12)\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)
  2. (2)12tan⁡−1(−12)\frac{1}{\sqrt{2}}\tan^{-1}\left(-\frac{1}{2}\right)Official answer
  3. (3)−12tan⁡−1(12)-\frac{1}{\sqrt{2}}\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)
  4. (4)12tan⁡−1(12)\frac{1}{2}\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)

Official answer

Option 2

NTA final key.

Chapter
Integrals